3113404117 has 4 divisors (see below), whose sum is σ = 3124978380. Its totient is φ = 3101829856.

The previous prime is 3113404097. The next prime is 3113404139. The reversal of 3113404117 is 7114043113.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 294431281 + 2818972836 = 17159^2 + 53094^2 .

It is a cyclic number.

It is not a de Polignac number, because 3113404117 - 2¹¹ = 3113402069 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3113404091 and 3113404100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3113404717) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5786728 + ... + 5787265.

It is an arithmetic number, because the mean of its divisors is an integer number (781244595).

Almost surely, 2^3113404117 is an apocalyptic number.

It is an amenable number.

3113404117 is a deficient number, since it is larger than the sum of its proper divisors (11574263).

3113404117 is a wasteful number, since it uses less digits than its factorization.

3113404117 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11574262.

The product of its (nonzero) digits is 1008, while the sum is 25.

The square root of 3113404117 is about 55797.8863130137. The cubic root of 3113404117 is about 1460.1982774750.

The spelling of 3113404117 in words is "three billion, one hundred thirteen million, four hundred four thousand, one hundred seventeen".