311430000000001 has 8 divisors (see below), whose sum is σ = 327833703983520. Its totient is φ = 295027561151712.

The previous prime is 311429999999971. The next prime is 311430000000013. The reversal of 311430000000001 is 100000000034113.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 311430000000001 - 2¹¹ = 311429999997953 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (311430000000061) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 315778495 + ... + 316763188.

It is an arithmetic number, because the mean of its divisors is an integer number (40979212997940).

Almost surely, 2^{311430000000001} is an apocalyptic number.

It is an amenable number.

311430000000001 is a deficient number, since it is larger than the sum of its proper divisors (16403703983519).

311430000000001 is a wasteful number, since it uses less digits than its factorization.

311430000000001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 632567615.

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 311430000000001 its reverse (100000000034113), we get a palindrome (411430000034114).

The spelling of 311430000000001 in words is "three hundred eleven trillion, four hundred thirty billion, one", and thus it is an aban number.