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311430034113112 = 23129130153953729
BaseRepresentation
bin100011011001111100111010…
…0100011100100001001011000
31111211200102100112122122221001
41012303321310203210021120
5311304432202213104422
63022204552123154344
7122412035365422415
oct10663716443441130
91454612315578831
10311430034113112
119025a810324512
122ab192883759b4
13104a0959614465
1456c9418d3910c
152601023528227
hex11b3e748e4258

311430034113112 has 16 divisors (see below), whose sum is σ = 584383623287400. Its totient is φ = 155594401236480.

The previous prime is 311430034113097. The next prime is 311430034113257. The reversal of 311430034113112 is 211311430034113.

It is a super-4 number, since 4×3114300341131124 (a number of 59 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15076966537 + ... + 15076987192.

Almost surely, 2311430034113112 is an apocalyptic number.

It is an amenable number.

311430034113112 is a deficient number, since it is larger than the sum of its proper divisors (272953589174288).

311430034113112 is a wasteful number, since it uses less digits than its factorization.

311430034113112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30153955026 (or 30153955022 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 28.

Adding to 311430034113112 its reverse (211311430034113), we get a palindrome (522741464147225).

The spelling of 311430034113112 in words is "three hundred eleven trillion, four hundred thirty billion, thirty-four million, one hundred thirteen thousand, one hundred twelve".

Divisors: 1 2 4 8 1291 2582 5164 10328 30153953729 60307907458 120615814916 241231629832 38928754264139 77857508528278 155715017056556 311430034113112