Base | Representation |
---|---|
bin | 100011011001111100111010… |
… | …0100011100100001001011000 |
3 | 1111211200102100112122122221001 |
4 | 1012303321310203210021120 |
5 | 311304432202213104422 |
6 | 3022204552123154344 |
7 | 122412035365422415 |
oct | 10663716443441130 |
9 | 1454612315578831 |
10 | 311430034113112 |
11 | 9025a810324512 |
12 | 2ab192883759b4 |
13 | 104a0959614465 |
14 | 56c9418d3910c |
15 | 2601023528227 |
hex | 11b3e748e4258 |
311430034113112 has 16 divisors (see below), whose sum is σ = 584383623287400. Its totient is φ = 155594401236480.
The previous prime is 311430034113097. The next prime is 311430034113257. The reversal of 311430034113112 is 211311430034113.
It is a super-4 number, since 4×3114300341131124 (a number of 59 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15076966537 + ... + 15076987192.
Almost surely, 2311430034113112 is an apocalyptic number.
It is an amenable number.
311430034113112 is a deficient number, since it is larger than the sum of its proper divisors (272953589174288).
311430034113112 is a wasteful number, since it uses less digits than its factorization.
311430034113112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 30153955026 (or 30153955022 counting only the distinct ones).
The product of its (nonzero) digits is 2592, while the sum is 28.
Adding to 311430034113112 its reverse (211311430034113), we get a palindrome (522741464147225).
The spelling of 311430034113112 in words is "three hundred eleven trillion, four hundred thirty billion, thirty-four million, one hundred thirteen thousand, one hundred twelve".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.082 sec. • engine limits •