Base | Representation |
---|---|
bin | 100011011001111101000000… |
… | …0011111100111001001001000 |
3 | 1111211200102212111112110112212 |
4 | 1012303322000133213021020 |
5 | 311304433110001402100 |
6 | 3022205024040124252 |
7 | 122412043350026210 |
oct | 10663720037471110 |
9 | 1454612774473485 |
10 | 311430234403400 |
11 | 9025a903395582 |
12 | 2ab19323466688 |
13 | 104a098bc70918 |
14 | 56c9437795240 |
15 | 2601035ddd635 |
hex | 11b3e807e7248 |
311430234403400 has 96 divisors (see below), whose sum is σ = 871068024120000. Its totient is φ = 101156286654720.
The previous prime is 311430234403283. The next prime is 311430234403423. The reversal of 311430234403400 is 4304432034113.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 5853925175 + ... + 5853978374.
It is an arithmetic number, because the mean of its divisors is an integer number (9073625251250).
Almost surely, 2311430234403400 is an apocalyptic number.
It is an amenable number.
311430234403400 is an abundant number, since it is smaller than the sum of its proper divisors (559637789716600).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
311430234403400 is a wasteful number, since it uses less digits than its factorization.
311430234403400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11707903591 (or 11707903582 counting only the distinct ones).
The product of its (nonzero) digits is 41472, while the sum is 32.
Adding to 311430234403400 its reverse (4304432034113), we get a palindrome (315734666437513).
The spelling of 311430234403400 in words is "three hundred eleven trillion, four hundred thirty billion, two hundred thirty-four million, four hundred three thousand, four hundred".
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