311431310304343 has 2 divisors, whose sum is σ = 311431310304344. Its totient is φ = 311431310304342.

The previous prime is 311431310304341. The next prime is 311431310304479. The reversal of 311431310304343 is 343403013134113.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 311431310304343 - 2¹ = 311431310304341 is a prime.

It is a super-2 number, since 2×311431310304343² (a number of 30 digits) contains 22 as substring.

Together with 311431310304341, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 311431310304299 and 311431310304308.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (311431310304341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155715655152171 + 155715655152172.

It is an arithmetic number, because the mean of its divisors is an integer number (155715655152172).

Almost surely, 2^{311431310304343} is an apocalyptic number.

311431310304343 is a deficient number, since it is larger than the sum of its proper divisors (1).

311431310304343 is an equidigital number, since it uses as much as digits as its factorization.

311431310304343 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 46656, while the sum is 34.

Adding to 311431310304343 its reverse (343403013134113), we get a palindrome (654834323438456).

The spelling of 311431310304343 in words is "three hundred eleven trillion, four hundred thirty-one billion, three hundred ten million, three hundred four thousand, three hundred forty-three".