Base | Representation |
---|---|
bin | 100011011001111101100000… |
… | …0100111110110010011011111 |
3 | 1111211200112122111000220100222 |
4 | 1012303323000213312103133 |
5 | 311304442310414220404 |
6 | 3022205322512311555 |
7 | 122412112123032101 |
oct | 10663730047662337 |
9 | 1454615574026328 |
10 | 311431310304479 |
11 | 9026030573aa22 |
12 | 2ab195838425bb |
13 | 104a0b00b34591 |
14 | 56c94da61d571 |
15 | 260109a5b3dbe |
hex | 11b3ec09f64df |
311431310304479 has 2 divisors, whose sum is σ = 311431310304480. Its totient is φ = 311431310304478.
The previous prime is 311431310304343. The next prime is 311431310304481. The reversal of 311431310304479 is 974403013134113.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-311431310304479 is a prime.
It is a super-2 number, since 2×3114313103044792 (a number of 30 digits) contains 22 as substring.
Together with 311431310304481, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (311431310300479) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155715655152239 + 155715655152240.
It is an arithmetic number, because the mean of its divisors is an integer number (155715655152240).
Almost surely, 2311431310304479 is an apocalyptic number.
311431310304479 is a deficient number, since it is larger than the sum of its proper divisors (1).
311431310304479 is an equidigital number, since it uses as much as digits as its factorization.
311431310304479 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 326592, while the sum is 44.
The spelling of 311431310304479 in words is "three hundred eleven trillion, four hundred thirty-one billion, three hundred ten million, three hundred four thousand, four hundred seventy-nine".
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