311440333431133 has 2 divisors, whose sum is σ = 311440333431134. Its totient is φ = 311440333431132.

The previous prime is 311440333431131. The next prime is 311440333431151. The reversal of 311440333431133 is 331134333044113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 261723704227129 + 49716629204004 = 16177877^2 + 7051002^2 .

It is an emirp because it is prime and its reverse (331134333044113) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 311440333431133 - 2¹ = 311440333431131 is a prime.

Together with 311440333431131, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 311440333431092 and 311440333431101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (311440333431131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155720166715566 + 155720166715567.

It is an arithmetic number, because the mean of its divisors is an integer number (155720166715567).

Almost surely, 2^{311440333431133} is an apocalyptic number.

It is an amenable number.

311440333431133 is a deficient number, since it is larger than the sum of its proper divisors (1).

311440333431133 is an equidigital number, since it uses as much as digits as its factorization.

311440333431133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 139968, while the sum is 37.

Adding to 311440333431133 its reverse (331134333044113), we get a palindrome (642574666475246).

The spelling of 311440333431133 in words is "three hundred eleven trillion, four hundred forty billion, three hundred thirty-three million, four hundred thirty-one thousand, one hundred thirty-three".