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31145151131032 = 2324918115623759
BaseRepresentation
bin1110001010011100010111…
…01010110110110110011000
311002021110002010120122002011
413011032023222312312120
513040240232142143112
6150123515050115304
76363106610402251
oct705161352666630
9132243063518064
1031145151131032
119a18647952074
1235b018011bb34
13144bc8a5322b3
1479960d1c3b28
153902545bcaa7
hex1c538bab6d98

31145151131032 has 16 divisors (see below), whose sum is σ = 58397396464800. Its totient is φ = 15572512073760.

The previous prime is 31145151131021. The next prime is 31145151131057. The reversal of 31145151131032 is 23013115154113.

It is a happy number.

It is a junction number, because it is equal to n+sod(n) for n = 31145151130985 and 31145151131003.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5818432 + ... + 9805327.

It is an arithmetic number, because the mean of its divisors is an integer number (3649837279050).

Almost surely, 231145151131032 is an apocalyptic number.

It is an amenable number.

31145151131032 is a deficient number, since it is larger than the sum of its proper divisors (27252245333768).

31145151131032 is a wasteful number, since it uses less digits than its factorization.

31145151131032 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15872946 (or 15872942 counting only the distinct ones).

The product of its (nonzero) digits is 5400, while the sum is 31.

Adding to 31145151131032 its reverse (23013115154113), we get a palindrome (54158266285145).

The spelling of 31145151131032 in words is "thirty-one trillion, one hundred forty-five billion, one hundred fifty-one million, one hundred thirty-one thousand, thirty-two".

Divisors: 1 2 4 8 249181 498362 996724 1993448 15623759 31247518 62495036 124990072 3893143891379 7786287782758 15572575565516 31145151131032