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31146371460053 is a prime number
BaseRepresentation
bin1110001010011110101000…
…11010000010101111010101
311002021120020011211202210022
413011033110122002233111
513040300232043210203
6150124240122034525
76363152056126643
oct705172432025725
9132246204752708
1031146371460053
119a19113783353
1235b0460948a45
13144c1232c3885
147996c72c6193
153902c67c1a38
hex1c53d4682bd5

31146371460053 has 2 divisors, whose sum is σ = 31146371460054. Its totient is φ = 31146371460052.

The previous prime is 31146371459993. The next prime is 31146371460103. The reversal of 31146371460053 is 35006417364113.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 15899861176369 + 15246510283684 = 3987463^2 + 3904678^2 .

It is a cyclic number.

It is not a de Polignac number, because 31146371460053 - 212 = 31146371455957 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 31146371459986 and 31146371460013.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31146371460653) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15573185730026 + 15573185730027.

It is an arithmetic number, because the mean of its divisors is an integer number (15573185730027).

Almost surely, 231146371460053 is an apocalyptic number.

It is an amenable number.

31146371460053 is a deficient number, since it is larger than the sum of its proper divisors (1).

31146371460053 is an equidigital number, since it uses as much as digits as its factorization.

31146371460053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 544320, while the sum is 44.

The spelling of 31146371460053 in words is "thirty-one trillion, one hundred forty-six billion, three hundred seventy-one million, four hundred sixty thousand, fifty-three".