31200104431 has 4 divisors (see below), whose sum is σ = 31200921432. Its totient is φ = 31199287432.

The previous prime is 31200104399. The next prime is 31200104483. The reversal of 31200104431 is 13440100213.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13440100213 = 47 ⋅285959579.

It is a cyclic number.

It is not a de Polignac number, because 31200104431 - 2⁵ = 31200104399 is a prime.

It is a super-2 number, since 2×31200104431² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 31200104399 and 31200104408.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31200104731) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 348256 + ... + 428581.

It is an arithmetic number, because the mean of its divisors is an integer number (7800230358).

Almost surely, 2^31200104431 is an apocalyptic number.

31200104431 is a deficient number, since it is larger than the sum of its proper divisors (817001).

31200104431 is an equidigital number, since it uses as much as digits as its factorization.

31200104431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 817000.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 31200104431 its reverse (13440100213), we get a palindrome (44640204644).

The spelling of 31200104431 in words is "thirty-one billion, two hundred million, one hundred four thousand, four hundred thirty-one".