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3120142055 = 53831629317
BaseRepresentation
bin1011100111111001…
…1001011011100111
322001110002122020212
42321332121123213
522342224021210
61233335250035
7140214525032
oct27176313347
98043078225
103120142055
1113612699a8
12730b1991b
133a955b004
1421855c019
15133dc6805
hexb9f996e7

3120142055 has 8 divisors (see below), whose sum is σ = 3753948672. Its totient is φ = 2489594848.

The previous prime is 3120142037. The next prime is 3120142063. The reversal of 3120142055 is 5502410213.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 3120142055 - 218 = 3119879911 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 3120142055.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 812744 + ... + 816573.

It is an arithmetic number, because the mean of its divisors is an integer number (469243584).

Almost surely, 23120142055 is an apocalyptic number.

3120142055 is a deficient number, since it is larger than the sum of its proper divisors (633806617).

3120142055 is a wasteful number, since it uses less digits than its factorization.

3120142055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1629705.

The product of its (nonzero) digits is 1200, while the sum is 23.

The square root of 3120142055 is about 55858.2317568324. The cubic root of 3120142055 is about 1461.2508912757.

Adding to 3120142055 its reverse (5502410213), we get a palindrome (8622552268).

The spelling of 3120142055 in words is "three billion, one hundred twenty million, one hundred forty-two thousand, fifty-five".

Divisors: 1 5 383 1915 1629317 8146585 624028411 3120142055