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312038999999 is a prime number
BaseRepresentation
bin1001000101001101111…
…10010100011110111111
31002211102112102121000222
410202212332110132333
520103023440444444
6355203154411555
731354421510606
oct4424676243677
91084375377028
10312038999999
11110375976181
1250585290bbb
132356b099a4c
1411161dd2a3d
1581b4584eee
hex48a6f947bf

312038999999 has 2 divisors, whose sum is σ = 312039000000. Its totient is φ = 312038999998.

The previous prime is 312038999939. The next prime is 312039000001. The reversal of 312038999999 is 999999830213.

It is a strong prime.

It is an emirp because it is prime and its reverse (999999830213) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 312038999999 - 236 = 243319523263 is a prime.

Together with 312039000001, it forms a pair of twin primes.

It is a Chen prime.

312038999999 is a modest number, since divided by 999999 gives 312038 as remainder.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (312038999929) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156019499999 + 156019500000.

It is an arithmetic number, because the mean of its divisors is an integer number (156019500000).

Almost surely, 2312038999999 is an apocalyptic number.

312038999999 is a deficient number, since it is larger than the sum of its proper divisors (1).

312038999999 is an equidigital number, since it uses as much as digits as its factorization.

312038999999 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 76527504, while the sum is 71.

The spelling of 312038999999 in words is "three hundred twelve billion, thirty-eight million, nine hundred ninety-nine thousand, nine hundred ninety-nine".