Base | Representation |
---|---|
bin | 11101000100010000… |
… | …110000000111010101 |
3 | 2222120002010221100122 |
4 | 131010100300013111 |
5 | 1002404230410031 |
6 | 22200534521325 |
7 | 2153261506646 |
oct | 350420600725 |
9 | 88502127318 |
10 | 31210013141 |
11 | 1226626989a |
12 | 6070206245 |
13 | 2c34c840c8 |
14 | 17210236cd |
15 | c29e9147b |
hex | 7444301d5 |
31210013141 has 2 divisors, whose sum is σ = 31210013142. Its totient is φ = 31210013140.
The previous prime is 31210013129. The next prime is 31210013167. The reversal of 31210013141 is 14131001213.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 25266374116 + 5943639025 = 158954^2 + 77095^2 .
It is a cyclic number.
It is not a de Polignac number, because 31210013141 - 26 = 31210013077 is a prime.
It is a super-2 number, since 2×312100131412 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31210013101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15605006570 + 15605006571.
It is an arithmetic number, because the mean of its divisors is an integer number (15605006571).
Almost surely, 231210013141 is an apocalyptic number.
It is an amenable number.
31210013141 is a deficient number, since it is larger than the sum of its proper divisors (1).
31210013141 is an equidigital number, since it uses as much as digits as its factorization.
31210013141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 31210013141 its reverse (14131001213), we get a palindrome (45341014354).
The spelling of 31210013141 in words is "thirty-one billion, two hundred ten million, thirteen thousand, one hundred forty-one".
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