Base | Representation |
---|---|
bin | 100011011110111010000001… |
… | …0011110100100001100000000 |
3 | 1111221002112002121202000222102 |
4 | 1012331310002132210030000 |
5 | 311402111332110000000 |
6 | 3023445453450125532 |
7 | 122512164014103014 |
oct | 10675640236441400 |
9 | 1457075077660872 |
10 | 312111020000000 |
11 | 904a25a4088541 |
12 | 2b0092591208a8 |
13 | 1051cc34711ba0 |
14 | 571037ac70544 |
15 | 2613acd1a93d5 |
hex | 11bdd027a4300 |
312111020000000 has 576 divisors, whose sum is σ = 856532813520384. Its totient is φ = 112784640000000.
The previous prime is 312111019999963. The next prime is 312111020000023. The reversal of 312111020000000 is 20111213.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 12219987230 + ... + 12220012770.
It is an arithmetic number, because the mean of its divisors is an integer number (1487036134584).
Almost surely, 2312111020000000 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 312111020000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (428266406760192).
312111020000000 is an abundant number, since it is smaller than the sum of its proper divisors (544421793520384).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
312111020000000 is an frugal number, since it uses more digits than its factorization.
312111020000000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25652 (or 25608 counting only the distinct ones).
The product of its (nonzero) digits is 12, while the sum is 11.
Adding to 312111020000000 its reverse (20111213), we get a palindrome (312111040111213).
The spelling of 312111020000000 in words is "three hundred twelve trillion, one hundred eleven billion, twenty million", and thus it is an aban number.
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