Base | Representation |
---|---|
bin | 101101011010110001110… |
… | …110000101001001100111 |
3 | 102001101011220201212220102 |
4 | 231122301312011021213 |
5 | 402114033240012444 |
6 | 10345454411454315 |
7 | 441331340164043 |
oct | 55326166051147 |
9 | 12041156655812 |
10 | 3121130000999 |
11 | aa373357731a |
12 | 424a9015739b |
13 | 198423b704ca |
14 | ab0c634b023 |
15 | 562c3a0984e |
hex | 2d6b1d85267 |
3121130000999 has 8 divisors (see below), whose sum is σ = 3122185825920. Its totient is φ = 3120074353656.
The previous prime is 3121130000983. The next prime is 3121130001001. The reversal of 3121130000999 is 9990000311213.
3121130000999 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 3121130000999 - 24 = 3121130000983 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3121130000699) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 41398952 + ... + 41474274.
It is an arithmetic number, because the mean of its divisors is an integer number (390273228240).
Almost surely, 23121130000999 is an apocalyptic number.
3121130000999 is a deficient number, since it is larger than the sum of its proper divisors (1055824921).
3121130000999 is an equidigital number, since it uses as much as digits as its factorization.
3121130000999 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 88789.
The product of its (nonzero) digits is 13122, while the sum is 38.
The spelling of 3121130000999 in words is "three trillion, one hundred twenty-one billion, one hundred thirty million, nine hundred ninety-nine", and thus it is an aban number.
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