Base | Representation |
---|---|
bin | 100011011110111110101011… |
… | …1001000000101000000111100 |
3 | 1111221010110221020111221221200 |
4 | 1012331331113020011000330 |
5 | 311402242332201244400 |
6 | 3023454231033255500 |
7 | 122513000043424041 |
oct | 10675752710050074 |
9 | 1457113836457850 |
10 | 312121030103100 |
11 | 904a6870573119 |
12 | 2b00b191564590 |
13 | 10520b6b528b0a |
14 | 5710a4a4a31c8 |
15 | 2613eb6db0b00 |
hex | 11bdf5720503c |
312121030103100 has 1728 divisors, whose sum is σ = 1133123955425280. Its totient is φ = 71404388352000.
The previous prime is 312121030103027. The next prime is 312121030103119. The reversal of 312121030103100 is 1301030121213.
312121030103100 is a `hidden beast` number, since 3 + 121 + 210 + 301 + 0 + 31 + 0 + 0 = 666.
It is a super-2 number, since 2×3121210301031002 (a number of 30 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 575 ways as a sum of consecutive naturals, for example, 271173787525 + ... + 271173788675.
It is an arithmetic number, because the mean of its divisors is an integer number (655743029760).
Almost surely, 2312121030103100 is an apocalyptic number.
312121030103100 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 312121030103100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (566561977712640).
312121030103100 is an abundant number, since it is smaller than the sum of its proper divisors (821002925322180).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
312121030103100 is a wasteful number, since it uses less digits than its factorization.
312121030103100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1660 (or 1650 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 18.
Adding to 312121030103100 its reverse (1301030121213), we get a palindrome (313422060224313).
The spelling of 312121030103100 in words is "three hundred twelve trillion, one hundred twenty-one billion, thirty million, one hundred three thousand, one hundred".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.084 sec. • engine limits •