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312122112000 = 211353478647
BaseRepresentation
bin1001000101010111110…
…11010111100000000000
31002211122022211010021020
410202223323113200000
520103211230041000
6355215324025440
731356451114626
oct4425373274000
91084568733236
10312122112000
11110408882486
12505a9092280
132358237974a
141116d069516
1581bba00ba0
hex48abed7800

312122112000 has 384 divisors, whose sum is σ = 1060706949120. Its totient is φ = 81452236800.

The previous prime is 312122111993. The next prime is 312122112011. The reversal of 312122112000 is 211221213.

It is a tau number, because it is divible by the number of its divisors (384).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 36091677 + ... + 36100323.

It is an arithmetic number, because the mean of its divisors is an integer number (2762257680).

Almost surely, 2312122112000 is an apocalyptic number.

312122112000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 312122112000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (530353474560).

312122112000 is an abundant number, since it is smaller than the sum of its proper divisors (748584837120).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

312122112000 is an equidigital number, since it uses as much as digits as its factorization.

312122112000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8734 (or 8704 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 312122112000 its reverse (211221213), we get a palindrome (312333333213).

The spelling of 312122112000 in words is "three hundred twelve billion, one hundred twenty-two million, one hundred twelve thousand".