Search a number
-
+
312131110200 = 233527135996893
BaseRepresentation
bin1001000101011000111…
…01101100010100111000
31002211122221202021110220
410202230131230110320
520103221031011300
6355220244540040
731356620442510
oct4425435542470
91084587667426
10312131110200
11110412968a08
12505b00b1620
13235841aa320
141117032c840
1581bc6cbda0
hex48ac76c538

312131110200 has 384 divisors, whose sum is σ = 1211097484800. Its totient is φ = 64739358720.

The previous prime is 312131110183. The next prime is 312131110289. The reversal of 312131110200 is 2011131213.

It is a happy number.

312131110200 is digitally balanced in base 7, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 312131110200.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 3172954 + ... + 3269846.

It is an arithmetic number, because the mean of its divisors is an integer number (3153899700).

Almost surely, 2312131110200 is an apocalyptic number.

312131110200 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 312131110200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (605548742400).

312131110200 is an abundant number, since it is smaller than the sum of its proper divisors (898966374600).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

312131110200 is a wasteful number, since it uses less digits than its factorization.

312131110200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 96991 (or 96982 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 312131110200 its reverse (2011131213), we get a palindrome (314142241413).

The spelling of 312131110200 in words is "three hundred twelve billion, one hundred thirty-one million, one hundred ten thousand, two hundred".