Base | Representation |
---|---|
bin | 100011011111000011011000… |
… | …0110010110011111110001110 |
3 | 1111221011102222201201222222110 |
4 | 1012332012300302303332032 |
5 | 311402424020322143202 |
6 | 3023503020425324450 |
7 | 122513505144556656 |
oct | 10676066062637616 |
9 | 1457142881658873 |
10 | 312131124412302 |
11 | 90500080542018 |
12 | 2b01112a036726 |
13 | 10521ab9916740 |
14 | 5711326d75366 |
15 | 26143a819c26c |
hex | 11be1b0cb3f8e |
312131124412302 has 32 divisors (see below), whose sum is σ = 672307942707072. Its totient is φ = 96036700130784.
The previous prime is 312131124412301. The next prime is 312131124412357. The reversal of 312131124412302 is 203214421131213.
It is a self number, because there is not a number n which added to its sum of digits gives 312131124412302.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (312131124412301) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 73886808 + ... + 77996939.
It is an arithmetic number, because the mean of its divisors is an integer number (21009623209596).
Almost surely, 2312131124412302 is an apocalyptic number.
312131124412302 is an abundant number, since it is smaller than the sum of its proper divisors (360176818294770).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
312131124412302 is a wasteful number, since it uses less digits than its factorization.
312131124412302 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 151910112.
The product of its (nonzero) digits is 6912, while the sum is 30.
Adding to 312131124412302 its reverse (203214421131213), we get a palindrome (515345545543515).
The spelling of 312131124412302 in words is "three hundred twelve trillion, one hundred thirty-one billion, one hundred twenty-four million, four hundred twelve thousand, three hundred two".
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