Base | Representation |
---|---|
bin | 100011011111000100010011… |
… | …1001101000010110000101110 |
3 | 1111221011122010011212010010200 |
4 | 1012332020213031002300232 |
5 | 311402442102404000420 |
6 | 3023503545513014330 |
7 | 122513605316361111 |
oct | 10676104715026056 |
9 | 1457148104763120 |
10 | 312133111000110 |
11 | 905009aa958924 |
12 | 2b0115a33b43a6 |
13 | 1052204537609a |
14 | 5711474b3c578 |
15 | 26144727b0b90 |
hex | 11be227342c2e |
312133111000110 has 288 divisors, whose sum is σ = 883498002510240. Its totient is φ = 76388368716288.
The previous prime is 312133111000103. The next prime is 312133111000111. The reversal of 312133111000110 is 11000111331213.
312133111000110 is a `hidden beast` number, since 3 + 121 + 331 + 1 + 100 + 0 + 110 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (312133111000111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 274720849 + ... + 275854691.
It is an arithmetic number, because the mean of its divisors is an integer number (3067701397605).
Almost surely, 2312133111000110 is an apocalyptic number.
312133111000110 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 312133111000110, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (441749001255120).
312133111000110 is an abundant number, since it is smaller than the sum of its proper divisors (571364891510130).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
312133111000110 is a wasteful number, since it uses less digits than its factorization.
312133111000110 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1134160 (or 1134138 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 18.
Adding to 312133111000110 its reverse (11000111331213), we get a palindrome (323133222331323).
The spelling of 312133111000110 in words is "three hundred twelve trillion, one hundred thirty-three billion, one hundred eleven million, one hundred ten", and thus it is an aban number.
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