Base | Representation |
---|---|
bin | 101101011010111110100… |
… | …110100101010010011101 |
3 | 102001101201211111022011010 |
4 | 231122332212211102131 |
5 | 402120003033322031 |
6 | 10345531535245433 |
7 | 441336546411513 |
oct | 55327646452235 |
9 | 12041654438133 |
10 | 3121344042141 |
11 | aa383337a626 |
12 | 424b2b979879 |
13 | 198459302880 |
14 | ab1069464b3 |
15 | 562d76d9246 |
hex | 2d6be9a549d |
3121344042141 has 32 divisors (see below), whose sum is σ = 4507970463360. Its totient is φ = 1909699190784.
The previous prime is 3121344042101. The next prime is 3121344042251. The reversal of 3121344042141 is 1412404431213.
It is a happy number.
It is not a de Polignac number, because 3121344042141 - 210 = 3121344041117 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3121344042099 and 3121344042108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3121344042101) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4303090 + ... + 4975868.
It is an arithmetic number, because the mean of its divisors is an integer number (140874076980).
Almost surely, 23121344042141 is an apocalyptic number.
It is an amenable number.
3121344042141 is a deficient number, since it is larger than the sum of its proper divisors (1386626421219).
3121344042141 is a wasteful number, since it uses less digits than its factorization.
3121344042141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 673485.
The product of its (nonzero) digits is 9216, while the sum is 30.
Adding to 3121344042141 its reverse (1412404431213), we get a palindrome (4533748473354).
The spelling of 3121344042141 in words is "three trillion, one hundred twenty-one billion, three hundred forty-four million, forty-two thousand, one hundred forty-one".
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