Base | Representation |
---|---|
bin | 1110001100100111110100… |
… | …11100001011111110110000 |
3 | 11002112121100011002111010012 |
4 | 13012103322130023332300 |
5 | 13043002102121003212 |
6 | 150222140411354052 |
7 | 6401400204316241 |
oct | 706237234137660 |
9 | 132477304074105 |
10 | 31220024000432 |
11 | 9a4737970a033 |
12 | 3602796a52928 |
13 | 1456060385b07 |
14 | 79d0b3046cc8 |
15 | 3921878c1922 |
hex | 1c64fa70bfb0 |
31220024000432 has 40 divisors (see below), whose sum is σ = 60776804327232. Its totient is φ = 15535810368000.
The previous prime is 31220024000351. The next prime is 31220024000441. The reversal of 31220024000432 is 23400042002213.
It is a junction number, because it is equal to n+sod(n) for n = 31220024000398 and 31220024000407.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 220682 + ... + 7904982.
Almost surely, 231220024000432 is an apocalyptic number.
It is an amenable number.
31220024000432 is a deficient number, since it is larger than the sum of its proper divisors (29556780326800).
31220024000432 is a wasteful number, since it uses less digits than its factorization.
31220024000432 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7685517 (or 7685511 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 23.
Adding to 31220024000432 its reverse (23400042002213), we get a palindrome (54620066002645).
The spelling of 31220024000432 in words is "thirty-one trillion, two hundred twenty billion, twenty-four million, four hundred thirty-two", and thus it is an aban number.
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