312404131113367 has 2 divisors, whose sum is σ = 312404131113368. Its totient is φ = 312404131113366.

The previous prime is 312404131113301. The next prime is 312404131113407. The reversal of 312404131113367 is 763311131404213.

It is an a-pointer prime, because the next prime (312404131113407) can be obtained adding 312404131113367 to its sum of digits (40).

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-312404131113367 is a prime.

It is a super-2 number, since 2×312404131113367² (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (312404131113967) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156202065556683 + 156202065556684.

It is an arithmetic number, because the mean of its divisors is an integer number (156202065556684).

Almost surely, 2^{312404131113367} is an apocalyptic number.

312404131113367 is a deficient number, since it is larger than the sum of its proper divisors (1).

312404131113367 is an equidigital number, since it uses as much as digits as its factorization.

312404131113367 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108864, while the sum is 40.

The spelling of 312404131113367 in words is "three hundred twelve trillion, four hundred four billion, one hundred thirty-one million, one hundred thirteen thousand, three hundred sixty-seven".