Base | Representation |
---|---|
bin | 100011100001000010100000… |
… | …1010000101110100110111111 |
3 | 1111222010112200001000100212122 |
4 | 1013002011001100232212333 |
5 | 311421412130031112112 |
6 | 3024232250534353155 |
7 | 122542311412336034 |
oct | 10702050120564677 |
9 | 1458115601010778 |
10 | 312404131113407 |
11 | 905a5936722333 |
12 | 2b05601b4bb7bb |
13 | 1054177726c928 |
14 | 57206250db38b |
15 | 261b535b9b872 |
hex | 11c214142e9bf |
312404131113407 has 2 divisors, whose sum is σ = 312404131113408. Its totient is φ = 312404131113406.
The previous prime is 312404131113367. The next prime is 312404131113469. The reversal of 312404131113407 is 704311131404213.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 312404131113407 - 212 = 312404131109311 is a prime.
It is a super-2 number, since 2×3124041311134072 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (312404131713407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156202065556703 + 156202065556704.
It is an arithmetic number, because the mean of its divisors is an integer number (156202065556704).
Almost surely, 2312404131113407 is an apocalyptic number.
312404131113407 is a deficient number, since it is larger than the sum of its proper divisors (1).
312404131113407 is an equidigital number, since it uses as much as digits as its factorization.
312404131113407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24192, while the sum is 35.
The spelling of 312404131113407 in words is "three hundred twelve trillion, four hundred four billion, one hundred thirty-one million, one hundred thirteen thousand, four hundred seven".
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