Base | Representation |
---|---|
bin | 1110001101001111010001… |
… | …11100001110011001101110 |
3 | 11002121122000022100020001010 |
4 | 13012213220330032121232 |
5 | 13043323442020324200 |
6 | 150240002255130050 |
7 | 6403050122036406 |
oct | 706475074163156 |
9 | 132548008306033 |
10 | 31241205245550 |
11 | 9a553589a4a93 |
12 | 3606908513926 |
13 | 14580576b9451 |
14 | 7a0122179806 |
15 | 3929c71c1150 |
hex | 1c69e8f0e66e |
31241205245550 has 48 divisors (see below), whose sum is σ = 77484096093312. Its totient is φ = 8330352895200.
The previous prime is 31241205245533. The next prime is 31241205245611. The reversal of 31241205245550 is 5554250214213.
It is a junction number, because it is equal to n+sod(n) for n = 31241205245499 and 31241205245508.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 5964016 + ... + 9902115.
It is an arithmetic number, because the mean of its divisors is an integer number (1614252001944).
Almost surely, 231241205245550 is an apocalyptic number.
31241205245550 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
31241205245550 is an abundant number, since it is smaller than the sum of its proper divisors (46242890847762).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31241205245550 is a wasteful number, since it uses less digits than its factorization.
31241205245550 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15879273 (or 15879268 counting only the distinct ones).
The product of its (nonzero) digits is 240000, while the sum is 39.
Adding to 31241205245550 its reverse (5554250214213), we get a palindrome (36795455459763).
The spelling of 31241205245550 in words is "thirty-one trillion, two hundred forty-one billion, two hundred five million, two hundred forty-five thousand, five hundred fifty".
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