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313002211217 is a prime number
BaseRepresentation
bin1001000111000000110…
…00101011011110010001
31002220220122212210102112
410203200120223132101
520112012031224332
6355442523355105
731420325616563
oct4434030533621
91086818783375
10313002211217
1111081a652003
12507b3982a95
13236927c5c07
1411213cc5333
15821ddeadb2
hex48e062b791

313002211217 has 2 divisors, whose sum is σ = 313002211218. Its totient is φ = 313002211216.

The previous prime is 313002211199. The next prime is 313002211219. The reversal of 313002211217 is 712112200313.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 168973612096 + 144028599121 = 411064^2 + 379511^2 .

It is a cyclic number.

It is not a de Polignac number, because 313002211217 - 220 = 313001162641 is a prime.

Together with 313002211219, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 313002211192 and 313002211201.

It is not a weakly prime, because it can be changed into another prime (313002211219) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156501105608 + 156501105609.

It is an arithmetic number, because the mean of its divisors is an integer number (156501105609).

Almost surely, 2313002211217 is an apocalyptic number.

It is an amenable number.

313002211217 is a deficient number, since it is larger than the sum of its proper divisors (1).

313002211217 is an equidigital number, since it uses as much as digits as its factorization.

313002211217 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 504, while the sum is 23.

The spelling of 313002211217 in words is "three hundred thirteen billion, two million, two hundred eleven thousand, two hundred seventeen".