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31300405543 = 112845491413
BaseRepresentation
bin11101001001101001…
…100100100100100111
32222210101020100102101
4131021221210210213
51003100400434133
622213524152531
72155440025441
oct351151444447
988711210371
1031300405543
1112302298a60
126096538747
132c4a912834
14172d033491
15c32d9937d
hex749a64927

31300405543 has 4 divisors (see below), whose sum is σ = 34145896968. Its totient is φ = 28454914120.

The previous prime is 31300405471. The next prime is 31300405571. The reversal of 31300405543 is 34550400313.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-31300405543 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31300405043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1422745696 + ... + 1422745717.

It is an arithmetic number, because the mean of its divisors is an integer number (8536474242).

Almost surely, 231300405543 is an apocalyptic number.

31300405543 is a deficient number, since it is larger than the sum of its proper divisors (2845491425).

31300405543 is a wasteful number, since it uses less digits than its factorization.

31300405543 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2845491424.

The product of its (nonzero) digits is 10800, while the sum is 28.

Adding to 31300405543 its reverse (34550400313), we get a palindrome (65850805856).

The spelling of 31300405543 in words is "thirty-one billion, three hundred million, four hundred five thousand, five hundred forty-three".

Divisors: 1 11 2845491413 31300405543