Base | Representation |
---|---|
bin | 100011100101101111111000… |
… | …0001010010100100111110100 |
3 | 1112001102102011002021200110010 |
4 | 1013023133300022110213310 |
5 | 312013013040444310200 |
6 | 3025445441531500220 |
7 | 122640132210610362 |
oct | 10713376012244764 |
9 | 1461372132250403 |
10 | 313051310541300 |
11 | 9082535162a351 |
12 | 2b13b5365b7670 |
13 | 1058a7c54b8c76 |
14 | 5743a9b254632 |
15 | 262d2b295e150 |
hex | 11cb7f02949f4 |
313051310541300 has 144 divisors (see below), whose sum is σ = 935002453012992. Its totient is φ = 80785487500800.
The previous prime is 313051310541283. The next prime is 313051310541317. The reversal of 313051310541300 is 3145013150313.
It is an interprime number because it is at equal distance from previous prime (313051310541283) and next prime (313051310541317).
It is a super-2 number, since 2×3130513105413002 (a number of 30 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 407449102 + ... + 408216698.
It is an arithmetic number, because the mean of its divisors is an integer number (6493072590368).
Almost surely, 2313051310541300 is an apocalyptic number.
313051310541300 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
313051310541300 is an abundant number, since it is smaller than the sum of its proper divisors (621951142471692).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
313051310541300 is a wasteful number, since it uses less digits than its factorization.
313051310541300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 811498 (or 811491 counting only the distinct ones).
The product of its (nonzero) digits is 8100, while the sum is 30.
Adding to 313051310541300 its reverse (3145013150313), we get a palindrome (316196323691613).
The spelling of 313051310541300 in words is "three hundred thirteen trillion, fifty-one billion, three hundred ten million, five hundred forty-one thousand, three hundred".
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