Base | Representation |
---|---|
bin | 11101001010010010… |
… | …100001100101101001 |
3 | 2222211010102210000020 |
4 | 131022102201211221 |
5 | 1003111123004400 |
6 | 22214550231053 |
7 | 2155630211010 |
oct | 351222414551 |
9 | 88733383006 |
10 | 31311141225 |
11 | 12308360921 |
12 | 609a055489 |
13 | 2c4cc01200 |
14 | 1730629a77 |
15 | c33cba2a0 |
hex | 74a4a1969 |
31311141225 has 288 divisors, whose sum is σ = 68054215680. Its totient is φ = 12416302080.
The previous prime is 31311141221. The next prime is 31311141317. The reversal of 31311141225 is 52214111313.
It is not a de Polignac number, because 31311141225 - 22 = 31311141221 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 31311141195 and 31311141204.
It is not an unprimeable number, because it can be changed into a prime (31311141221) by changing a digit.
It is a polite number, since it can be written in 287 ways as a sum of consecutive naturals, for example, 110639934 + ... + 110640216.
It is an arithmetic number, because the mean of its divisors is an integer number (236299360).
Almost surely, 231311141225 is an apocalyptic number.
31311141225 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
It is an amenable number.
31311141225 is an abundant number, since it is smaller than the sum of its proper divisors (36743074455).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31311141225 is a wasteful number, since it uses less digits than its factorization.
31311141225 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 401 (or 383 counting only the distinct ones).
The product of its digits is 720, while the sum is 24.
Adding to 31311141225 its reverse (52214111313), we get a palindrome (83525252538).
The spelling of 31311141225 in words is "thirty-one billion, three hundred eleven million, one hundred forty-one thousand, two hundred twenty-five".
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