Base | Representation |
---|---|
bin | 100011100110011011001111… |
… | …1010000100011101110100111 |
3 | 1112001202022112121111111000221 |
4 | 1013030312133100203232213 |
5 | 312021024304240031210 |
6 | 3030000323152545211 |
7 | 122646640130325013 |
oct | 10714663720435647 |
9 | 1461668477444027 |
10 | 313144442502055 |
11 | 908608a315195a |
12 | 2b1555a8252207 |
13 | 10596518146858 |
14 | 57483b40a9543 |
15 | 2630913c491da |
hex | 11ccd9f423ba7 |
313144442502055 has 4 divisors (see below), whose sum is σ = 375773331002472. Its totient is φ = 250515554001640.
The previous prime is 313144442502041. The next prime is 313144442502109. The reversal of 313144442502055 is 550205244441313.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 313144442502055 - 29 = 313144442501543 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31314444250201 + ... + 31314444250210.
It is an arithmetic number, because the mean of its divisors is an integer number (93943332750618).
Almost surely, 2313144442502055 is an apocalyptic number.
313144442502055 is a deficient number, since it is larger than the sum of its proper divisors (62628888500417).
313144442502055 is an equidigital number, since it uses as much as digits as its factorization.
313144442502055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 62628888500416.
The product of its (nonzero) digits is 1152000, while the sum is 43.
Adding to 313144442502055 its reverse (550205244441313), we get a palindrome (863349686943368).
The spelling of 313144442502055 in words is "three hundred thirteen trillion, one hundred forty-four billion, four hundred forty-two million, five hundred two thousand, fifty-five".
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