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313144442502055 = 562628888500411
BaseRepresentation
bin100011100110011011001111…
…1010000100011101110100111
31112001202022112121111111000221
41013030312133100203232213
5312021024304240031210
63030000323152545211
7122646640130325013
oct10714663720435647
91461668477444027
10313144442502055
11908608a315195a
122b1555a8252207
1310596518146858
1457483b40a9543
152630913c491da
hex11ccd9f423ba7

313144442502055 has 4 divisors (see below), whose sum is σ = 375773331002472. Its totient is φ = 250515554001640.

The previous prime is 313144442502041. The next prime is 313144442502109. The reversal of 313144442502055 is 550205244441313.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 313144442502055 - 29 = 313144442501543 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31314444250201 + ... + 31314444250210.

It is an arithmetic number, because the mean of its divisors is an integer number (93943332750618).

Almost surely, 2313144442502055 is an apocalyptic number.

313144442502055 is a deficient number, since it is larger than the sum of its proper divisors (62628888500417).

313144442502055 is an equidigital number, since it uses as much as digits as its factorization.

313144442502055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 62628888500416.

The product of its (nonzero) digits is 1152000, while the sum is 43.

Adding to 313144442502055 its reverse (550205244441313), we get a palindrome (863349686943368).

The spelling of 313144442502055 in words is "three hundred thirteen trillion, one hundred forty-four billion, four hundred forty-two million, five hundred two thousand, fifty-five".

Divisors: 1 5 62628888500411 313144442502055