Base | Representation |
---|---|
bin | 101101100101111100100… |
… | …100100111100111001000 |
3 | 102002112010121011111122110 |
4 | 231211330210213213020 |
5 | 402313113002224000 |
6 | 10355200323222320 |
7 | 442234443134415 |
oct | 55457444474710 |
9 | 12075117144573 |
10 | 3133121133000 |
11 | aa8827221271 |
12 | 427277b179a0 |
13 | 1995b521b7a1 |
14 | ab902adb10c |
15 | 567765c7850 |
hex | 2d97c9279c8 |
3133121133000 has 64 divisors (see below), whose sum is σ = 9775337944320. Its totient is φ = 835498968000.
The previous prime is 3133121132957. The next prime is 3133121133001. The reversal of 3133121133000 is 3311213313.
It is not an unprimeable number, because it can be changed into a prime (3133121133001) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 522183856 + ... + 522189855.
It is an arithmetic number, because the mean of its divisors is an integer number (152739655380).
Almost surely, 23133121133000 is an apocalyptic number.
3133121133000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
3133121133000 is an abundant number, since it is smaller than the sum of its proper divisors (6642216811320).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3133121133000 is a wasteful number, since it uses less digits than its factorization.
3133121133000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1044373735 (or 1044373721 counting only the distinct ones).
The product of its (nonzero) digits is 486, while the sum is 21.
Adding to 3133121133000 its reverse (3311213313), we get a palindrome (3136432346313).
The spelling of 3133121133000 in words is "three trillion, one hundred thirty-three billion, one hundred twenty-one million, one hundred thirty-three thousand".
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