Base | Representation |
---|---|
bin | 1110001111111010010100… |
… | …01111100100100010000111 |
3 | 11002221102000212121200202020 |
4 | 13013331022033210202013 |
5 | 13101330022144120403 |
6 | 150350110213414223 |
7 | 6412510512533322 |
oct | 707751217444207 |
9 | 132842025550666 |
10 | 31333032020103 |
11 | 9a9029a7a7910 |
12 | 362067503a373 |
13 | 14638ccb145c8 |
14 | 7a475391d7b9 |
15 | 39509dae4453 |
hex | 1c7f4a3e4887 |
31333032020103 has 64 divisors (see below), whose sum is σ = 46150202442240. Its totient is φ = 18751258944000.
The previous prime is 31333032020083. The next prime is 31333032020167. The reversal of 31333032020103 is 30102023033313.
It is not a de Polignac number, because 31333032020103 - 221 = 31333029922951 is a prime.
It is a super-2 number, since 2×313330320201032 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31333032420103) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2069682108 + ... + 2069697246.
It is an arithmetic number, because the mean of its divisors is an integer number (721096913160).
Almost surely, 231333032020103 is an apocalyptic number.
31333032020103 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
31333032020103 is a deficient number, since it is larger than the sum of its proper divisors (14817170422137).
31333032020103 is a wasteful number, since it uses less digits than its factorization.
31333032020103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16880.
The product of its (nonzero) digits is 2916, while the sum is 24.
Adding to 31333032020103 its reverse (30102023033313), we get a palindrome (61435055053416).
The spelling of 31333032020103 in words is "thirty-one trillion, three hundred thirty-three billion, thirty-two million, twenty thousand, one hundred three".
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