313433114011231 has 4 divisors (see below), whose sum is σ = 314440937529264. Its totient is φ = 312425290493200.

The previous prime is 313433114011223. The next prime is 313433114011273. The reversal of 313433114011231 is 132110411334313.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 313433114011231 - 2³ = 313433114011223 is a prime.

It is a super-2 number, since 2×313433114011231² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 313433114011193 and 313433114011202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (313433114041231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 503911758550 + ... + 503911759171.

It is an arithmetic number, because the mean of its divisors is an integer number (78610234382316).

Almost surely, 2^{313433114011231} is an apocalyptic number.

313433114011231 is a deficient number, since it is larger than the sum of its proper divisors (1007823518033).

313433114011231 is a wasteful number, since it uses less digits than its factorization.

313433114011231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1007823518032.

The product of its (nonzero) digits is 7776, while the sum is 31.

Adding to 313433114011231 its reverse (132110411334313), we get a palindrome (445543525345544).

The spelling of 313433114011231 in words is "three hundred thirteen trillion, four hundred thirty-three billion, one hundred fourteen million, eleven thousand, two hundred thirty-one".