Base | Representation |
---|---|
bin | 1110010000001101011101… |
… | …11111011000110010100000 |
3 | 11002222101120022121111200002 |
4 | 13020012232333120302200 |
5 | 13102012100411223404 |
6 | 150354530245515132 |
7 | 6413323331652545 |
oct | 710065677306240 |
9 | 132871508544602 |
10 | 31343312211104 |
11 | 9a94695696533 |
12 | 3622663a12aa8 |
13 | 146487a88536a |
14 | 7a504ad7abcc |
15 | 3954a139bc1e |
hex | 1c81aefd8ca0 |
31343312211104 has 96 divisors (see below), whose sum is σ = 66239579298816. Its totient is φ = 14546078392320.
The previous prime is 31343312211103. The next prime is 31343312211221. The reversal of 31343312211104 is 40111221334313.
It is a super-2 number, since 2×313433122111042 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (31343312211103) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 389574209 + ... + 389654655.
It is an arithmetic number, because the mean of its divisors is an integer number (689995617696).
Almost surely, 231343312211104 is an apocalyptic number.
31343312211104 is a gapful number since it is divisible by the number (34) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 31343312211104, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (33119789649408).
31343312211104 is an abundant number, since it is smaller than the sum of its proper divisors (34896267087712).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31343312211104 is a wasteful number, since it uses less digits than its factorization.
31343312211104 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 90358 (or 90350 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 31343312211104 its reverse (40111221334313), we get a palindrome (71454533545417).
It can be divided in two parts, 3134331 and 2211104, that added together give a palindrome (5345435).
The spelling of 31343312211104 in words is "thirty-one trillion, three hundred forty-three billion, three hundred twelve million, two hundred eleven thousand, one hundred four".
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