Base | Representation |
---|---|
bin | 1110010000010001101001… |
… | …01000110001110001000000 |
3 | 11002222121100120202002011220 |
4 | 13020020310220301301000 |
5 | 13102031143413243130 |
6 | 150355540544235040 |
7 | 6413433026344113 |
oct | 710106450616100 |
9 | 132877316662156 |
10 | 31345554431040 |
11 | 9a95636332563 |
12 | 3622b8a90ba80 |
13 | 1464b47279b15 |
14 | 7a51c0a8857a |
15 | 395583158410 |
hex | 1c8234a31c40 |
31345554431040 has 112 divisors (see below), whose sum is σ = 99523349157120. Its totient is φ = 8358712565760.
The previous prime is 31345554430991. The next prime is 31345554431077. The reversal of 31345554431040 is 4013445554313.
It is a junction number, because it is equal to n+sod(n) for n = 31345554430983 and 31345554431001.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 110710776 + ... + 110993544.
It is an arithmetic number, because the mean of its divisors is an integer number (888601331760).
Almost surely, 231345554431040 is an apocalyptic number.
31345554431040 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
31345554431040 is an abundant number, since it is smaller than the sum of its proper divisors (68177794726080).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31345554431040 is a wasteful number, since it uses less digits than its factorization.
31345554431040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 398260 (or 398250 counting only the distinct ones).
The product of its (nonzero) digits is 864000, while the sum is 42.
Adding to 31345554431040 its reverse (4013445554313), we get a palindrome (35358999985353).
The spelling of 31345554431040 in words is "thirty-one trillion, three hundred forty-five billion, five hundred fifty-four million, four hundred thirty-one thousand, forty".
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