3140012501 has 2 divisors, whose sum is σ = 3140012502. Its totient is φ = 3140012500.

The previous prime is 3140012483. The next prime is 3140012503. The reversal of 3140012501 is 1052100413.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1739307025 + 1400705476 = 41705^2 + 37426^2 .

It is a cyclic number.

It is not a de Polignac number, because 3140012501 - 2¹⁰ = 3140011477 is a prime.

Together with 3140012503, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 3140012501.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3140012503) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1570006250 + 1570006251.

It is an arithmetic number, because the mean of its divisors is an integer number (1570006251).

Almost surely, 2^3140012501 is an apocalyptic number.

It is an amenable number.

3140012501 is a deficient number, since it is larger than the sum of its proper divisors (1).

3140012501 is an equidigital number, since it uses as much as digits as its factorization.

3140012501 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 3140012501 is about 56035.8144493323. The cubic root of 3140012501 is about 1464.3462937881.

Adding to 3140012501 its reverse (1052100413), we get a palindrome (4192112914).

The spelling of 3140012501 in words is "three billion, one hundred forty million, twelve thousand, five hundred one".