Base | Representation |
---|---|
bin | 100011101100101111101100… |
… | …1100111101101011100101101 |
3 | 1112011211100110020011012110110 |
4 | 1013121133121213231130231 |
5 | 312124242113242343001 |
6 | 3031503325534330233 |
7 | 123066455665162311 |
oct | 10731373147553455 |
9 | 1464740406135413 |
10 | 314013005043501 |
11 | 91066193054845 |
12 | 2b2759a8059979 |
13 | 1062a3b77a527a |
14 | 577844c183b41 |
15 | 26482eb3583d6 |
hex | 11d97d99ed72d |
314013005043501 has 64 divisors (see below), whose sum is σ = 460218916961280. Its totient is φ = 189652924661760.
The previous prime is 314013005043497. The next prime is 314013005043541. The reversal of 314013005043501 is 105340500310413.
It is not a de Polignac number, because 314013005043501 - 22 = 314013005043497 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (314013005043541) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1338791805 + ... + 1339026333.
It is an arithmetic number, because the mean of its divisors is an integer number (7190920577520).
Almost surely, 2314013005043501 is an apocalyptic number.
It is an amenable number.
314013005043501 is a deficient number, since it is larger than the sum of its proper divisors (146205911917779).
314013005043501 is a wasteful number, since it uses less digits than its factorization.
314013005043501 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 243814.
The product of its (nonzero) digits is 10800, while the sum is 30.
Adding to 314013005043501 its reverse (105340500310413), we get a palindrome (419353505353914).
The spelling of 314013005043501 in words is "three hundred fourteen trillion, thirteen billion, five million, forty-three thousand, five hundred one".
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