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314115044435 = 51723497332309
BaseRepresentation
bin1001001001000101011…
…01110011010001010011
31010000210012212120121122
410210202231303101103
520121301422410220
6400145155312455
731460030552363
oct4444255632123
91100705776548
10314115044435
11111240832085
1250a645ab72b
132380c21abca
14112bba049a3
158286969425
hex4922b73453

314115044435 has 32 divisors (see below), whose sum is σ = 416560164480. Its totient is φ = 226174609408.

The previous prime is 314115044429. The next prime is 314115044449. The reversal of 314115044435 is 534440511413.

It is a cyclic number.

It is not a de Polignac number, because 314115044435 - 26 = 314115044371 is a prime.

It is a super-2 number, since 2×3141150444352 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 314115044395 and 314115044404.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 9706061 + ... + 9738369.

It is an arithmetic number, because the mean of its divisors is an integer number (13017505140).

Almost surely, 2314115044435 is an apocalyptic number.

314115044435 is a deficient number, since it is larger than the sum of its proper divisors (102445120045).

314115044435 is a wasteful number, since it uses less digits than its factorization.

314115044435 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37327.

The product of its (nonzero) digits is 57600, while the sum is 35.

Adding to 314115044435 its reverse (534440511413), we get a palindrome (848555555848).

The spelling of 314115044435 in words is "three hundred fourteen billion, one hundred fifteen million, forty-four thousand, four hundred thirty-five".

Divisors: 1 5 17 23 85 115 391 1955 4973 24865 32309 84541 114379 161545 422705 549253 571895 743107 1944443 2746265 3715535 9722215 12632819 63164095 160672657 803363285 2731435169 3695471111 13657175845 18477355555 62823008887 314115044435