Base | Representation |
---|---|
bin | 1001001001000101011… |
… | …01110011010001010011 |
3 | 1010000210012212120121122 |
4 | 10210202231303101103 |
5 | 20121301422410220 |
6 | 400145155312455 |
7 | 31460030552363 |
oct | 4444255632123 |
9 | 1100705776548 |
10 | 314115044435 |
11 | 111240832085 |
12 | 50a645ab72b |
13 | 2380c21abca |
14 | 112bba049a3 |
15 | 8286969425 |
hex | 4922b73453 |
314115044435 has 32 divisors (see below), whose sum is σ = 416560164480. Its totient is φ = 226174609408.
The previous prime is 314115044429. The next prime is 314115044449. The reversal of 314115044435 is 534440511413.
It is a cyclic number.
It is not a de Polignac number, because 314115044435 - 26 = 314115044371 is a prime.
It is a super-2 number, since 2×3141150444352 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 314115044395 and 314115044404.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 9706061 + ... + 9738369.
It is an arithmetic number, because the mean of its divisors is an integer number (13017505140).
Almost surely, 2314115044435 is an apocalyptic number.
314115044435 is a deficient number, since it is larger than the sum of its proper divisors (102445120045).
314115044435 is a wasteful number, since it uses less digits than its factorization.
314115044435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 37327.
The product of its (nonzero) digits is 57600, while the sum is 35.
Adding to 314115044435 its reverse (534440511413), we get a palindrome (848555555848).
The spelling of 314115044435 in words is "three hundred fourteen billion, one hundred fifteen million, forty-four thousand, four hundred thirty-five".
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