Base | Representation |
---|---|
bin | 101101101111001011011… |
… | …011001101001101011111 |
3 | 102010110201102222100001221 |
4 | 231233023123031031133 |
5 | 402443413201001343 |
6 | 10403520114314211 |
7 | 443035212125065 |
oct | 55571333151537 |
9 | 12113642870057 |
10 | 3143034000223 |
11 | 1001a53833117 |
12 | 429183888967 |
13 | 19a504b4c0b0 |
14 | ac1a345c035 |
15 | 56b569c35ed |
hex | 2dbcb6cd35f |
3143034000223 has 8 divisors (see below), whose sum is σ = 3562953522800. Its totient is φ = 2748564145728.
The previous prime is 3143034000193. The next prime is 3143034000247. The reversal of 3143034000223 is 3220004303413.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 3143034000223 - 25 = 3143034000191 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3143034000283) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6362416758 + ... + 6362417251.
It is an arithmetic number, because the mean of its divisors is an integer number (445369190350).
Almost surely, 23143034000223 is an apocalyptic number.
3143034000223 is a deficient number, since it is larger than the sum of its proper divisors (419919522577).
3143034000223 is a wasteful number, since it uses less digits than its factorization.
3143034000223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12724834041.
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 3143034000223 its reverse (3220004303413), we get a palindrome (6363038303636).
The spelling of 3143034000223 in words is "three trillion, one hundred forty-three billion, thirty-four million, two hundred twenty-three", and thus it is an aban number.
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