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3143104400111 = 13241777261547
BaseRepresentation
bin101101101111001111100…
…111110000101011101111
3102010110220100110000120012
4231233033213300223233
5402444034211300421
610403531111243435
7443040025405424
oct55571747605357
912113810400505
103143104400111
111001a8a547645
124291a337957b
1319a5165ca930
14ac1ac945d4b
1556b5cc7c95b
hex2dbcf9f0aef

3143104400111 has 4 divisors (see below), whose sum is σ = 3384881661672. Its totient is φ = 2901327138552.

The previous prime is 3143104400099. The next prime is 3143104400143. The reversal of 3143104400111 is 1110044013413.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3143104400111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3143104406111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 120888630761 + ... + 120888630786.

It is an arithmetic number, because the mean of its divisors is an integer number (846220415418).

Almost surely, 23143104400111 is an apocalyptic number.

3143104400111 is a deficient number, since it is larger than the sum of its proper divisors (241777261561).

3143104400111 is a wasteful number, since it uses less digits than its factorization.

3143104400111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 241777261560.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 3143104400111 its reverse (1110044013413), we get a palindrome (4253148413524).

The spelling of 3143104400111 in words is "three trillion, one hundred forty-three billion, one hundred four million, four hundred thousand, one hundred eleven".

Divisors: 1 13 241777261547 3143104400111