Base | Representation |
---|---|
bin | 101101101111001111100… |
… | …111110000101011101111 |
3 | 102010110220100110000120012 |
4 | 231233033213300223233 |
5 | 402444034211300421 |
6 | 10403531111243435 |
7 | 443040025405424 |
oct | 55571747605357 |
9 | 12113810400505 |
10 | 3143104400111 |
11 | 1001a8a547645 |
12 | 4291a337957b |
13 | 19a5165ca930 |
14 | ac1ac945d4b |
15 | 56b5cc7c95b |
hex | 2dbcf9f0aef |
3143104400111 has 4 divisors (see below), whose sum is σ = 3384881661672. Its totient is φ = 2901327138552.
The previous prime is 3143104400099. The next prime is 3143104400143. The reversal of 3143104400111 is 1110044013413.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3143104400111 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3143104406111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 120888630761 + ... + 120888630786.
It is an arithmetic number, because the mean of its divisors is an integer number (846220415418).
Almost surely, 23143104400111 is an apocalyptic number.
3143104400111 is a deficient number, since it is larger than the sum of its proper divisors (241777261561).
3143104400111 is a wasteful number, since it uses less digits than its factorization.
3143104400111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 241777261560.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 3143104400111 its reverse (1110044013413), we get a palindrome (4253148413524).
The spelling of 3143104400111 in words is "three trillion, one hundred forty-three billion, one hundred four million, four hundred thousand, one hundred eleven".
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