314334013 has 4 divisors (see below), whose sum is σ = 359238880. Its totient is φ = 269429148.

The previous prime is 314334011. The next prime is 314334019. The reversal of 314334013 is 310433413.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 310433413 = 17 ⋅18260789.

It is a cyclic number.

It is not a de Polignac number, because 314334013 - 2¹ = 314334011 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (314334011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22452423 + ... + 22452436.

It is an arithmetic number, because the mean of its divisors is an integer number (89809720).

Almost surely, 2^314334013 is an apocalyptic number.

It is an amenable number.

314334013 is a deficient number, since it is larger than the sum of its proper divisors (44904867).

314334013 is an equidigital number, since it uses as much as digits as its factorization.

314334013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 44904866.

The product of its (nonzero) digits is 1296, while the sum is 22.

The square root of 314334013 is about 17729.4673636858. The cubic root of 314334013 is about 679.9293561272.

Adding to 314334013 its reverse (310433413), we get a palindrome (624767426).

The spelling of 314334013 in words is "three hundred fourteen million, three hundred thirty-four thousand, thirteen".