Base | Representation |
---|---|
bin | 1001001001011111100… |
… | …01011011111000011111 |
3 | 1010001100111001210202121 |
4 | 10210233301123320133 |
5 | 20122224012213043 |
6 | 400223022403411 |
7 | 31465330526335 |
oct | 4445761337037 |
9 | 1101314053677 |
10 | 314334101023 |
11 | 111343450588 |
12 | 50b05a30567 |
13 | 238457180a7 |
14 | 112dcb47b55 |
15 | 829acd9ded |
hex | 492fc5be1f |
314334101023 has 2 divisors, whose sum is σ = 314334101024. Its totient is φ = 314334101022.
The previous prime is 314334101021. The next prime is 314334101027. The reversal of 314334101023 is 320101433413.
It is a weak prime.
It is an emirp because it is prime and its reverse (320101433413) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 314334101023 - 21 = 314334101021 is a prime.
Together with 314334101021, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (314334101021) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157167050511 + 157167050512.
It is an arithmetic number, because the mean of its divisors is an integer number (157167050512).
Almost surely, 2314334101023 is an apocalyptic number.
314334101023 is a deficient number, since it is larger than the sum of its proper divisors (1).
314334101023 is an equidigital number, since it uses as much as digits as its factorization.
314334101023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 314334101023 its reverse (320101433413), we get a palindrome (634435534436).
The spelling of 314334101023 in words is "three hundred fourteen billion, three hundred thirty-four million, one hundred one thousand, twenty-three".
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