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314341047486145 = 5232733400412923
BaseRepresentation
bin100011101111001000011101…
…0011110010100011011000001
31112012222201012001212220201101
41013132100322132110123001
5312200130431124024040
63032314141134334401
7123132251123012341
oct10736207236243301
91465881161786641
10314341047486145
11911823204a7279
122b30949895a401
13106523062621b4
14578a28b762d21
152651aea86409a
hex11de43a7946c1

314341047486145 has 8 divisors (see below), whose sum is σ = 393609659461056. Its totient is φ = 240539236337136.

The previous prime is 314341047486143. The next prime is 314341047486161. The reversal of 314341047486145 is 541684740143413.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 314341047486145 - 21 = 314341047486143 is a prime.

It is a super-2 number, since 2×3143410474861452 (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (314341047486143) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1366700206347 + ... + 1366700206576.

It is an arithmetic number, because the mean of its divisors is an integer number (49201207432632).

Almost surely, 2314341047486145 is an apocalyptic number.

It is an amenable number.

314341047486145 is a deficient number, since it is larger than the sum of its proper divisors (79268611974911).

314341047486145 is a wasteful number, since it uses less digits than its factorization.

314341047486145 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2733400412951.

The product of its (nonzero) digits is 15482880, while the sum is 55.

The spelling of 314341047486145 in words is "three hundred fourteen trillion, three hundred forty-one billion, forty-seven million, four hundred eighty-six thousand, one hundred forty-five".

Divisors: 1 5 23 115 2733400412923 13667002064615 62868209497229 314341047486145