Base | Representation |
---|---|
bin | 1110010011000010010111… |
… | …01110101001010010001111 |
3 | 11010022200020200222112200000 |
4 | 13021201023232221102033 |
5 | 13110110000332010042 |
6 | 150511311253135343 |
7 | 6423332123056155 |
oct | 711411356512217 |
9 | 133280220875600 |
10 | 31440431125647 |
11 | a0218a27a1475 |
12 | 363944892a553 |
13 | 1470a875173bb |
14 | 7a9a2150b3d5 |
15 | 397c876d174c |
hex | 1c984bba948f |
31440431125647 has 12 divisors (see below), whose sum is σ = 47095954443720. Its totient is φ = 20960287416936.
The previous prime is 31440431125643. The next prime is 31440431125661. The reversal of 31440431125647 is 74652113404413.
31440431125647 is a `hidden beast` number, since 3 + 1 + 4 + 40 + 4 + 31 + 12 + 564 + 7 = 666.
It is not a de Polignac number, because 31440431125647 - 22 = 31440431125643 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31440431125643) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 64692244872 + ... + 64692245357.
It is an arithmetic number, because the mean of its divisors is an integer number (3924662870310).
Almost surely, 231440431125647 is an apocalyptic number.
31440431125647 is a deficient number, since it is larger than the sum of its proper divisors (15655523318073).
31440431125647 is an equidigital number, since it uses as much as digits as its factorization.
31440431125647 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 129384490244 (or 129384490232 counting only the distinct ones).
The product of its (nonzero) digits is 967680, while the sum is 45.
The spelling of 31440431125647 in words is "thirty-one trillion, four hundred forty billion, four hundred thirty-one million, one hundred twenty-five thousand, six hundred forty-seven".
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