Base | Representation |
---|---|
bin | 100011110000101001111111… |
… | …1000101100000110011111111 |
3 | 1112020201201211111020221202011 |
4 | 1013201103333011200303333 |
5 | 312212043413124300210 |
6 | 3032554301253512051 |
7 | 123153344506324351 |
oct | 10741237705406377 |
9 | 1466651744227664 |
10 | 314550504525055 |
11 | 91253135542807 |
12 | 2b341bb3642627 |
13 | 10668ca6924186 |
14 | 579647b82b0d1 |
15 | 26572a9193d8a |
hex | 11e14ff160cff |
314550504525055 has 64 divisors (see below), whose sum is σ = 430067010539520. Its totient is φ = 219385926144000.
The previous prime is 314550504525013. The next prime is 314550504525071. The reversal of 314550504525055 is 550525405055413.
It is not a de Polignac number, because 314550504525055 - 223 = 314550496136447 is a prime.
It is a super-2 number, since 2×3145505045250552 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 76248355 + ... + 80267755.
It is an arithmetic number, because the mean of its divisors is an integer number (6719797039680).
Almost surely, 2314550504525055 is an apocalyptic number.
314550504525055 is a deficient number, since it is larger than the sum of its proper divisors (115516506014465).
314550504525055 is a wasteful number, since it uses less digits than its factorization.
314550504525055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4020520.
The product of its (nonzero) digits is 7500000, while the sum is 49.
The spelling of 314550504525055 in words is "three hundred fourteen trillion, five hundred fifty billion, five hundred four million, five hundred twenty-five thousand, fifty-five".
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