Base | Representation |
---|---|
bin | 11101010101111000… |
… | …000100110010100101 |
3 | 10000022200012221220222 |
4 | 131111320010302211 |
5 | 1004010404042432 |
6 | 22250132534125 |
7 | 2163510423101 |
oct | 352570046245 |
9 | 100280187828 |
10 | 31505534117 |
11 | 123a8064102 |
12 | 6133181345 |
13 | 2c812742a5 |
14 | 174c38c901 |
15 | c45db8112 |
hex | 755e04ca5 |
31505534117 has 2 divisors, whose sum is σ = 31505534118. Its totient is φ = 31505534116.
The previous prime is 31505534059. The next prime is 31505534119. The reversal of 31505534117 is 71143550513.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 30732193636 + 773340481 = 175306^2 + 27809^2 .
It is a cyclic number.
It is not a de Polignac number, because 31505534117 - 28 = 31505533861 is a prime.
Together with 31505534119, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31505534119) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15752767058 + 15752767059.
It is an arithmetic number, because the mean of its divisors is an integer number (15752767059).
Almost surely, 231505534117 is an apocalyptic number.
It is an amenable number.
31505534117 is a deficient number, since it is larger than the sum of its proper divisors (1).
31505534117 is an equidigital number, since it uses as much as digits as its factorization.
31505534117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31500, while the sum is 35.
The spelling of 31505534117 in words is "thirty-one billion, five hundred five million, five hundred thirty-four thousand, one hundred seventeen".
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