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315231131020 = 225131212427427
BaseRepresentation
bin1001001011001010011…
…11010101010110001100
31010010122222222122120211
410211211033111112030
520131043132143040
6400452025052204
731526502255211
oct4454517252614
91103588878524
10315231131020
11111763834493
1251116327064
1323959511980
1411385d2db08
1582ee92b8ea
hex49653d558c

315231131020 has 24 divisors (see below), whose sum is σ = 712907327664. Its totient is φ = 116393032896.

The previous prime is 315231131003. The next prime is 315231131071. The reversal of 315231131020 is 20131132513.

It is a junction number, because it is equal to n+sod(n) for n = 315231130982 and 315231131000.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 606213454 + ... + 606213973.

It is an arithmetic number, because the mean of its divisors is an integer number (29704471986).

Almost surely, 2315231131020 is an apocalyptic number.

It is an amenable number.

315231131020 is an abundant number, since it is smaller than the sum of its proper divisors (397676196644).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

315231131020 is a wasteful number, since it uses less digits than its factorization.

315231131020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1212427449 (or 1212427447 counting only the distinct ones).

The product of its (nonzero) digits is 540, while the sum is 22.

Adding to 315231131020 its reverse (20131132513), we get a palindrome (335362263533).

The spelling of 315231131020 in words is "three hundred fifteen billion, two hundred thirty-one million, one hundred thirty-one thousand, twenty".

Divisors: 1 2 4 5 10 13 20 26 52 65 130 260 1212427427 2424854854 4849709708 6062137135 12124274270 15761556551 24248548540 31523113102 63046226204 78807782755 157615565510 315231131020