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3157252136581 is a prime number
BaseRepresentation
bin101101111100011010111…
…001000101111010000101
3102011211102022220111110211
4231330122321011322011
5403212023021332311
610414231022315421
7444050436235504
oct55743271057205
912154368814424
103157252136581
111007a8a581434
1242ba91428b71
1319b95c6c532a
14acb518b883b
15571d9d44821
hex2df1ae45e85

3157252136581 has 2 divisors, whose sum is σ = 3157252136582. Its totient is φ = 3157252136580.

The previous prime is 3157252136579. The next prime is 3157252136609. The reversal of 3157252136581 is 1856312527513.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2226347489025 + 930904647556 = 1492095^2 + 964834^2 .

It is a cyclic number.

It is not a de Polignac number, because 3157252136581 - 21 = 3157252136579 is a prime.

It is a super-2 number, since 2×31572521365812 (a number of 26 digits) contains 22 as substring.

Together with 3157252136579, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3157252136551) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1578626068290 + 1578626068291.

It is an arithmetic number, because the mean of its divisors is an integer number (1578626068291).

Almost surely, 23157252136581 is an apocalyptic number.

It is an amenable number.

3157252136581 is a deficient number, since it is larger than the sum of its proper divisors (1).

3157252136581 is an equidigital number, since it uses as much as digits as its factorization.

3157252136581 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1512000, while the sum is 49.

The spelling of 3157252136581 in words is "three trillion, one hundred fifty-seven billion, two hundred fifty-two million, one hundred thirty-six thousand, five hundred eighty-one".