Base | Representation |
---|---|
bin | 101110000001001010001… |
… | …010101110010101001111 |
3 | 102012022112221002200212012 |
4 | 232001022022232111033 |
5 | 403302433101130210 |
6 | 10420431542331435 |
7 | 444320511441242 |
oct | 56011212562517 |
9 | 12168487080765 |
10 | 3162340255055 |
11 | 100a1606a5123 |
12 | 430a71429b7b |
13 | 19c290897617 |
14 | ad0b5557259 |
15 | 573d68a5305 |
hex | 2e04a2ae54f |
3162340255055 has 8 divisors (see below), whose sum is σ = 3832380666144. Its totient is φ = 2504823964000.
The previous prime is 3162340255031. The next prime is 3162340255073. The reversal of 3162340255055 is 5505520432613.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a de Polignac number, because none of the positive numbers 2k-3162340255055 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3131029451 + ... + 3131030460.
It is an arithmetic number, because the mean of its divisors is an integer number (479047583268).
Almost surely, 23162340255055 is an apocalyptic number.
3162340255055 is a deficient number, since it is larger than the sum of its proper divisors (670040411089).
3162340255055 is a wasteful number, since it uses less digits than its factorization.
3162340255055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6262060017.
The product of its (nonzero) digits is 540000, while the sum is 41.
Adding to 3162340255055 its reverse (5505520432613), we get a palindrome (8667860687668).
The spelling of 3162340255055 in words is "three trillion, one hundred sixty-two billion, three hundred forty million, two hundred fifty-five thousand, fifty-five".
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