Base | Representation |
---|---|
bin | 1001001110110000011… |
… | …10000000000001111111 |
3 | 1010022122102210112210201 |
4 | 10213120032000001333 |
5 | 20144021000131112 |
6 | 401411254544331 |
7 | 31625344614415 |
oct | 4473016000177 |
9 | 1108572715721 |
10 | 317160161407 |
11 | 112563708581 |
12 | 515743680a7 |
13 | 23ba606b07b |
14 | 114ca1d32b5 |
15 | 83b3e71257 |
hex | 49d838007f |
317160161407 has 2 divisors, whose sum is σ = 317160161408. Its totient is φ = 317160161406.
The previous prime is 317160161371. The next prime is 317160161443. The reversal of 317160161407 is 704161061713.
It is a balanced prime because it is at equal distance from previous prime (317160161371) and next prime (317160161443).
It is a cyclic number.
It is not a de Polignac number, because 317160161407 - 235 = 282800423039 is a prime.
It is a super-3 number, since 3×3171601614073 (a number of 35 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (317160161107) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 158580080703 + 158580080704.
It is an arithmetic number, because the mean of its divisors is an integer number (158580080704).
Almost surely, 2317160161407 is an apocalyptic number.
317160161407 is a deficient number, since it is larger than the sum of its proper divisors (1).
317160161407 is an equidigital number, since it uses as much as digits as its factorization.
317160161407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21168, while the sum is 37.
The spelling of 317160161407 in words is "three hundred seventeen billion, one hundred sixty million, one hundred sixty-one thousand, four hundred seven".
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